Double digger cakes 10 year olds
Therefore, when Peter said that he did not know the numbers, Sally would be able to know that the product Peter was told had to be 4. The only product that is ambiguous is 4 since 4 could be equal to 1 × 4 or 2 × 2. 25 → 5 × 5 The two numbers are 5 and 5.20 → 4 × 5 The two numbers are 4 and 5.16 → 4 × 4 The two numbers are 4 and 4.15 → 3 × 5 The two numbers are 3 and 5.12 → 3 × 4 The two numbers are 3 and 4.10 → 2 × 5 The two numbers are 2 and 5.Since each of them were each given numbers 1 to 5, if Peter was told any of the following numbers, he would be able to tell what the two numbers that were picked were: The number I was told is larger than the number you were told. Peter: I still don’t know the two numbers. They were then told to guess the two numbers. The sum of the numbers from the two cards was told only to Sally and the product of the numbers was told only to Peter. They were then blindfolded and told to pick a card from their respective sets. Sally was given a set of 5 cards numbered 1 to 5 and Peter was also given a set of 5 cards numbered 1 to 5.
![double digger cakes 10 year olds double digger cakes 10 year olds](https://www.merrimentdesign.com/images/easy-constrution-birthday-cake.jpg)
![double digger cakes 10 year olds double digger cakes 10 year olds](https://thebakingexplorer.com/wp-content/uploads/2020/02/Babybirthdaycakefeatured.jpg)
If the march can only travel East or South, what is the number of different possible ways to get to the Community Centre? ĥ. A march goes through the streets from the School (S) to the Community Centre (CC). If the four numbers are A, B, C and D, then we know that If we leave out any one number, the average of the remaining three numbers will be 45, 60, 65 or 70. Which means the height must be 30/6, or 70/14 = 5. So the edge bordering the 84 and 70 faces has length 14, and the edge bordering the 84 and 30 edges has length 6. The only way to make 84 with one each of these common factors are 14 from the top line and 6 from the bottom. The common factors between 84 and 30 are 1, 2, 3 and 6.The common factors between 84 and 70 are 1, 2, 7 and 14.The 30 face could be 1 x 30, 2 x 15, 3 x 10 or 5 x 6. The 70 face could be 1 x 70, 2 x 35, 5 x 14 or 7 x 10. įirst we need to work out the possible side lengths, by seeing which two numbers multiply to be the area of each face. Let’s now draw the string divided into twentieths: So, we cut off 8/20, subtract 14m and are left with 5/20. In order to compare the fractions 2/5 and then 1/4, lets change them to the lowest common denominator, which is 20. In other words, we are left with 1/4 of the original length. Then 14m, and are left with a piece that is a third of the size of what was cut. It requires us to think more visually about the string: We cut 2/5 of it.
![double digger cakes 10 year olds double digger cakes 10 year olds](https://images-na.ssl-images-amazon.com/images/I/71lLj1awp8L._AC_SL1200_.jpg)
Interestingly, the Singapore method of solution is different.
![double digger cakes 10 year olds double digger cakes 10 year olds](https://i5.walmartimages.com/asr/f34aa122-947c-4433-b090-6c0c88c76daf_1.c7b6bf48311183d774f092f6b2507769.jpeg)
Which rearranges to:7L/5 = 56, or L = 40. By substituting the first equation in the second we have 2L/5 + 14 = 9L/5 –42. Let L be the original length of the string, and R be what is remaining once you have cut the string twice. Oh Mary! This is how I would have solved it, using equations. What is the length of the remaining string? The ratio of the length of string remaining to the total length cut off is 1 : 3. Thanks for taking part - now look through your workings.ġ. The only questions where your most popular answer the wrong one were 6 and 8. On the whole you did very well - smarter than a 10-year-old Singaporean! (With the caveat that they didn’t have multiple choice answers to choose from, and they are only ten). Earlier today I set you ten questions from this year’s International Singapore Maths Competition.